Chapter 2
Models of Growth: Rates of Change





2.4 Exponential Functions

2.4.4 Derivatives of More General Exponential
         Functions

Have we really accomplished something by introducing \(e\) and concentrating on the one function exp ( t ) = e t ? Suppose we consider functions u ( t ) = e 3 t or v ( t ) = e 5 t or w ( t ) = e 2.35 t . How do we differentiate these functions? In general, we need to know how to differentiate functions of the form e k t , given that the derivative of e t is e t .

Activity 6  

  1. Use your graphing tool to plot f ( t ) = e k t , g ( t ) = f ( t + 0.001 ) - f ( t ) 0.001 , and their ratio, g ( t ) f ( t ) , for \(k=2, 3, 4.\)

  2. Conjecture a general formula for d d t e k t .

Comment 6Comment on Activity 6

Checkpoint 4Checkpoint 4

Now we establish a general formula for differentiation of exponential functions. Suppose \(A\) and \(k\) are constants. Then

d d t A e k t = A d d t e k t from the Constant Multiple Rule
           = A k e k t   from the formula in Activity 6
           = k A e k t   by commutativity of multiplication

Conclusion:

d d t A e k t = k A e k t .

Example 1   Calculate the derivative of 5 e 3 t .

Solution    d d t 5 e 3 t = 3 5 e 3 t = 15 e 3 t

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