Chapter 8
Integral Calculus and Its Uses
8.1 Moments and Centers of Mass
Problems
- Explain why the beam is balanced in Figure P1.
Figure P1 A balanced beam -
Figure P2 Office mobile -
Use an integral to explain the formula \(V=\frac{1}{3} \pi R^2 h\) for the volume of a circular cone of radius \(R\) at the base and height \(h\).
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Find the \(y\)-coordinate of the center of mass of the cone in Figure P3.
Figure P3 A circular cone of radius \(R\) and height \(h\) - The horn-shaped object in Figure P4 has circular cross sections. The radius \(r\) varies with \(x\) according to the formula
\(r(x)=\frac{1}{2} x^2\) for \(0 \leq x \leq 1\).
Find the volume of the horn.
Figure P4 A parabolic horn - The horn-shaped object in Figure P5 has circular cross sections. The radius \(r\) varies with \(x\) according to the formula
\(r(x)=\frac{1}{2} + x^2\) for \(0 \leq x \leq 1\).
Find the volume of the horn.
Figure P5 Another parabolic horn - The horn-shaped object in Figure P6 has circular cross sections. The radius \(r\) varies with \(x\) according to the formula
\(r(x)=\frac{1}{2} + \frac{1}{2} e^x\) for \(0 \leq x \leq 1\).
Find the volume of the horn.
Figure P6 An exponential horn - A cylindrical rod with diameter 10 centimeters and length 75 centimeters has a variable density. If we place the rod in a coordinate system as indicated in Figure P7, the density has the form
\(\delta (x) =0.01+0.0001 x\)
grams per cubic centimeter.
Figure P7 A cylindrical rod- Find the mass of the rod.
- Find the center of mass of the rod.
- A thin cylindrical rod with diameter 5 centimeters and length 90 centimeters has a variable density. If we place the rod in a coordinate system as indicated in Figure P8, the density has the form
\(\delta (x) =0.005+0.0002 x\)
grams per cubic centimeter.
Figure P8 A cylindrical rod- Find the mass of the rod.
- Find the center of mass of the rod.